/**
 * Exercise 7.10 p 251 b and c. Skip a.
 */
public class Exercise710 {

	/**
	 * Return the largest of the 3 doubles a, b and c
	 */
	public double maxOf(double a, double b, double c) {
		double max = a;
		if (max < b)
			max = b;
		if (max < c)
			max = c;
		return max;
	}

	/**
	 * Return the integer value of an hexadecimal character.<br>
	 * Return -1 if the character is not an hexadecimal character.
	 */
	public int hexValue(char c) {
		// To compute the integer values, use the characters' Unicode codes
		// e.g.for c='0',...,'9', c-'0' is understood as Unicode(c)-Unicode('0')
		// Since '0','1','2',...,'9' are in this order in Unicode,
		// c-'0' gives the integer value of the digit represented by c
		// Do the same thing with c='A',...,'F', but add 10 since A is 10
		// in hexadecimal.
		if (c >= '0' && c <= '9')
			return c - '0';
		else if (c >= 'A' && c <= 'F')
			return c - 'A' + 10;
		else
			return -1;
	}

	/**
	 * Starts the application
	 */
	public static void main(String[] args) {
		Exercise710 e = new Exercise710();
		System.out
				.println("e.maxOf(3.2, -5, 10.9) = " + e.maxOf(3.2, -5, 10.9));
		System.out.println("e.hexValue('B') = " + e.hexValue('B'));
	}
}